6+(x^2-x+10)=10

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Solution for 6+(x^2-x+10)=10 equation: 



6+(x^2-x+10)=10

We move all terms to the left:

6+(x^2-x+10)-(10)=0

We add all the numbers together, and all the variables

(x^2-x+10)-4=0

We get rid of parentheses

x^2-x+10-4=0

We add all the numbers together, and all the variables

x^2-1x+6=0

a = 1; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·1·6
Δ = -23
Delta is less than zero, so there is no solution for the equation

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